Question

solve the following system of linear equations graphically 2x-y-4=0,x+y+1=0

Answer 1

multiply x+y+1=0 with 2
⇒ the 2 equations are 2x-y-4=0 and 2x+2y+2=0
subtract 2 equation from first equation
⇒-3y-6=0
⇒-3y=6
⇒y=6/-3
⇒y=-2
substitute y = -2 in the equation x+y+1=0
⇒x-2+1=0
⇒x=1

Answer 2

Answer:

The solution of the system of equation is x=1 and y=-2.

Step-by-step explanation:

Given : System of equations $2x-y-4=0$ and $x+y+1=0$

To find : Solve the following system of linear equations graphically?

Solution :

Let $2x-y-4=0$ ........(1)

$x+y+1=0$ ..........(2)

Plot the two equations,

Equation (1) is in the red in color.

Equation (2) is in the blue in color.

The intersection of both the lines is the solution of the system.

Refer the attached figure below.

The intersection point is (1,-2).

Therefore, The solution of the system of equation is x=1 and y=-2.