Question

solve the following system of linear equations graphically 3x+ y-12=0 , x-3y+16=0.shade the region bounded by the lines and x axis also find the area of the shaded region

Answer 1

Step-by-step explanation:

3x+y-12

=3x+y=12

=y=12-3x

x-3y+16=0

=x-3y=-16

=x-3×12-3x=-16

=-2x-36=-16

=-2x=36-16

=-2x=20

=x=20/-2

=x=-10

3x+y-12=0

=3x+y=12

=3×10+y=12

=30+y=12

=y=12-30

=y=-18

I hope it may be useful.