Math, asked by swapnamadhu79, 1 year ago

solve the following system of linear equations graphically 3x-2y-1=0 ; 2x-3y+6=0 shade the region bounded by the lines and x-axis

Answers

Answered by tardymanchester
73

Answer:

Solution of the linear equation is x=3, y=4

Shaded region in black.

Step-by-step explanation:

Given : Equation 1- 3x-2y-1=0

Equation 2- 2x-3y+6=0

To find : Solve the following system of linear equations graphically 3x-2y-1=0 and 2x-3y+6=0 shade the region bounded by the lines and x-axis.

Solution : Graph is attached below.

The graph represent the area of the equation 1 , equation 2 and x-axis.

The point satisfying the equation is the intersection point of the graph

The intersection point of the graph is (3,4).

And the area under equation 1 , equation 2 and x-axis is the shaded region in black between the points (-3,0),(0,2),(3,4),(0.333,0) and x-axis.

Attachments:
Answered by nivethasenthilkumar2
0

Solution of the linear equation is x=3, y=4

Shaded region in black.

Step-by-step explanation:

Given : Equation 1-  

Equation 2-  

To find : Solve the following system of linear equations graphically  and  shade the region bounded by the lines and x-axis.

Solution : Graph is attached below.

The graph represent the area of the equation 1 , equation 2 and x-axis.

The point satisfying the equation is the intersection point of the graph

The intersection point of the graph is (3,4).

And the area under equation 1 , equation 2 and x-axis is the shaded region in black between the points (-3,0),(0,2),(3,4),(0.333,0) and x-axis.

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