Question

solve the following system of linear equations in three variables x+y+z=5;2x-y+z=9;x-2y+3y=16​

Answer 1

Answer:

Step-by-step explanation:

let us solve one by one

x + y + z = 5...........1.

x = 5-(y+z).........2.

now 2x- y +z = 9......3.

put x in 3.

2(5-(y+z)) -y + z = 9

10 -y -z-y + z = 9

10-2y=9

-2y= -1

y = 1/2 = 0.5

also given

x-2y+3y=16......5.

= x+y=16.........................6.

put y value in 5.

x + 1/2 = 16

x= 16 - 1/2

x= 31/2=15.5

put x and y value in 1.

15.5 + 0.5 +z =5

16 + z = 5

z= -9

Answer 2

Answer:

Step-by-step explanation:

let us solve one by one

x + y + z = 5...........1.

x = 5-(y+z).........2.

now 2x- y +z = 9......3.

put x in 3.

2(5-(y+z)) -y + z = 9

10 -y -z-y + z = 9

10-2y=9

-2y= -1

y = 1/2 = 0.5

also given

x-2y+3y=16......5.

= x+y=16.........................6.

put y value in 5.

x + 1/2 = 16

x= 16 - 1/2

x= 31/2=15.5

put x and y value in 1.

15.5 + 0.5 +z =5

16 + z = 5

z= -9