Math, asked by shashimounisha123, 10 months ago

Solve the following system of linear equations x+5y=13 x-4y=-5

Answers

Answered by Anonymous
6

Answer:

hloo..

.

ubtract EQ 2 from 1

5y+4y=18

9y=18

y=2

substituting y in EQ 1 x+10=13

x=3

hope it helps you

please mark it as the brainliest answer...

Answered by sonuvuce
1

The solutions of the equations are

x = 3, y = 2

Step-by-step explanation:

The given linear equations are

x+5y=13   ..................... (1)

x-4y=-5    ...................... (2)

Solving the simultaneous linear equations by the method of substitution

From equation (2)

x=-5+4y    ........................ (3)

Putting the value of x in equation (1)

-5+4y+5y=13

\implies 9y=18

\implies y=\frac{18}{9}

\implies y=2

Therefore, from equation (3)

x=-5+4\times 2

\implies x=-5+8

\implies x=3

Therefore, the solutions of the equations are

x = 3, y = 2

Hope this answer is helpful.

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