Question

Solve the following system of linear inequalities graphically x+2y ≤ 8, 2x+y≤ 8, x20, y20​

Answer 1

Answer:

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Step-by-step explanation:

First, we shall plot the graph of the equation and shade the side containing solutions of the inequality, Now, we can choose any value but find the two mandatory values which are at x = 0 and y = 0, i.e., x and y–intercepts always, x – y ≤ 1 Therefore when, x 0 2 1 y -1 1 0 x + 2y ≤ 8 Therefore when, x 0 4 8 y 4 2 0 2x + y ≥ 2 Therefore when, x 0 2 1 y 2 -2 0 x ≥ 0, y ≥ 0 Read more on Sarthaks.com - https://www.sarthaks.com/799883/solve-the-systems-of-linear-inequations-graphically-x-y-1-x-2y-8-2x-y-2-x-0-y-0