Question

Solve the following systems by Elimination by equating Coefficients method.
Please solve 13th ques No.
I will mark as a branliest one.

Answer 1

Hope this helps u Ms. Vijaya lakshmi Mehra.....
Please mark me as the brainliest.....

Answer 2

$Given : \frac{1}{3x} + \frac{y}{9} =5------ (1)$

$Given : \frac{1}{5x} + \frac{y}{2} = 16 ------ (2)$

On solving (1) * 15 & (2) * 25, we get

$\frac{15}{3x} + \frac{15y}{9} = 75$

$\frac{25}{5x} + \frac{25y}{2} = 400$

------------------------------------------------------------

                                15y/9 - 25y/2 = -325

                                -65y/6 = -325
 
                               -65y = 1950

                                   y = 30,



Substitute y = 30 in (1), we get

1/3x + y/9 = 5

1/3x + 30/9 = 5

LCM = 9x

3 + 30x = 45x

3 = 45x - 30x

3 = 15x

x = 3/15

x = 1/5



Therefore x = 1/5 and y = 30.


Hope this helps