Math, asked by VijayaLaxmiMehra1, 1 year ago

Solve the following systems by Elmination by Substitution method.
5x+3y-70=0 ; 3x-7y=60
Answer x= 335/22 , y= -45/22
(class 10th)

Answers

Answered by luckybadgujar9ovpgsr
18
we have 5x+3y-70=0 ---------(1) &
3x-7y=60 -----------(2)
Multiply first equation by 3
15x+9y = 210 ----------(3)
Multiply second equation by 5
15x-35y = 300 ----------------(4)
subtract 3 equation from 4
15x-35y-15x-9y = 300 - 210
-44y = 90
y = -90/44 = -45/22

putting value of y in 2 equation
3x-7(-45/22) = 60
3x+315/22 = 60
3x = 1005/22
x = 335/22
Hope it will help u plz......mark it as brainliest answer



luckybadgujar9ovpgsr: 3x = 1005/22
luckybadgujar9ovpgsr: x = 335/22
luckybadgujar9ovpgsr: okkk hope these steps will help u
luckybadgujar9ovpgsr: plz.....mark it as brainliest answer
VijayaLaxmiMehra1: 60-315= -255 na hoga
luckybadgujar9ovpgsr: divide m 22 bhi h
luckybadgujar9ovpgsr: L.C.M bhi lena hoga
luckybadgujar9ovpgsr: aaisa nhi hoga
VijayaLaxmiMehra1: Ab smjh gyi
alokpal47788: which class
Answered by alokpal47788
6
 5x+3y=70---------------(1)
3x-7y=60--------------(2)

15x+9y=210
15x-35y=300
-    +       -

44y= -90
y= -45/22
  put the value of (y) in eq (1)
5x+3y= 70
5x+3(-45/22)=70
5x-135/22=70
5x=70+135/22
5x=1675/22
x=335/5
i hope uunderstand
plz mark brainliest

alokpal47788: this is simple rule
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