Question

Solve the following systems of equations:1)x-2y=0;3x+4y=20

Answer 1

Elimination Method

x-2y=0.............1

3x+4y=20........2

For y

Multiply equation 1 by 3

we get,

3x   -  6y  =  0

3x  +  4y  =  20

(-)   (-)         (-)

---------------------

0      -10y = -20

-10y= -20

10y= 20

y=2

For x

multiply equation 1 by 2

we get,

2x  - 4y  = 0

3x  +4y  =20

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5x +0    =20

5x=20

x=4

hence, x =4 and y =2

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Answer 2

Answer:

x=4;y=5 ..............