Question

solve the following systems of equations:
1)x-2y=0
3x+4y=20
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Answer 1

hope the attachment will help u

Answer 2

let ,

x - 2y = 0 equation 1

and 3x + 4y = 20 equation 2

multiply with 3 in eq 1

so,

3x - 6y = 0 eq 3

solve the equation 2 and 3

so,

3x + 4y = 20

3x - 6y = 0

10 y = 20

y = 20/10 = 2

putting the value of y in equation 2

3x + 4y = 20

3x = 20 - 8

x. = 12/3 = 4

so value of x = 4

and value of y = 2