Question

Solve the following systems of equations:
3x-7y+10=0
y-2x-3=0

Answer 1

Given :

3x - 7y + 10 = 0

y - 2x - 3 = 0

 

Solution :  

Substitution method is used to solve this Linear pair of Equations:

Given , pair of system of equation is :

3x - 7y + 10 = 0 ……….... (1)

y - 2x - 3 = 0 ……….... (2)

From eq (2), we have  

y - 2x - 3 = 0

y = 2x + 3 …………. (3)

On Substituting the value of y in equation (1) we obtain ,

3x - 7(2x + 3) + 10 = 0

⇒ 3x + 14x - 21 + 10 = 0

⇒ -11x = 11

⇒ x = -1

Now , on putting  x = 2 in the eq (3), we obtain :

y = 2x + 3

⇒ y = 2(- 1) + 3

y = 1

Hence the solution of the given system of equation is x = - 1 and y = 1

Hope this answer will help you…

 

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Answer 2

The given system of equation is

3x - 7y + 0 = 0 ... (i)

y - 2x - 3 = 0 ..... (ii)

From (ii) , We Get

y = 2x + 3

Substituting y = 2x + 3 in (i) we get

$\bf 3x - 7(2x - 3) + 10 = 0$

$\bf \red→3x + 14x - 21 + 10 = 0$

$\bf \pink{→} - 11x = 11$

$\bf \orange{→}x = \frac{11}{ - 11} = - 1$

Putting X = -1 in y = 2x + 3,we get

$\bf \green{→}y = 2 x( 1 ) + 3$

$\bf \blue{→} - 2 + 3$

$\bf \purple{→}1$

$\bf \pink{→}y = 1$

Hence, The solution of the given system of equation is x = 1, y = 1.