Math, asked by aathifa6161, 8 months ago

Solve the following systems of equations :
5/(x – 1) + 1/(y – 2) = 2
6/(x – 1) – 3/(y – 2) = 1

Answers

Answered by meher786
1

Answer:

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Answered by topwriters
1

x = 4, y = 5

Step-by-step explanation:

Given linear equations are:

5/(x – 1) + 1/(y – 2) = 2

6/(x – 1) – 3/(y – 2) = 1

Let 1/x-1 = u and 1/y-2 = v, we get:

5u +v = 2-------------(1)

6u -3v = 1-------------(2)

(1)*3 will be 15u + 3v = 6

(2) will be 6u - 3v = 1

Adding both, we get: 21v = 7

Therefore v = 1/3

Substituting in equation 2, we get 6u -1 = 1

u = 1/3

1/x-1 = 1/3

So x-1 = 3.

Therefore x = 4.

1/y-2 = 1/3

So y-2 = 3

Therefore y = 5.

Hence solved. x = 4, y = 5

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