Solve the following systems of equations :
5/(x – 1) + 1/(y – 2) = 2
6/(x – 1) – 3/(y – 2) = 1
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x = 4, y = 5
Step-by-step explanation:
Given linear equations are:
5/(x – 1) + 1/(y – 2) = 2
6/(x – 1) – 3/(y – 2) = 1
Let 1/x-1 = u and 1/y-2 = v, we get:
5u +v = 2-------------(1)
6u -3v = 1-------------(2)
(1)*3 will be 15u + 3v = 6
(2) will be 6u - 3v = 1
Adding both, we get: 21v = 7
Therefore v = 1/3
Substituting in equation 2, we get 6u -1 = 1
u = 1/3
1/x-1 = 1/3
So x-1 = 3.
Therefore x = 4.
1/y-2 = 1/3
So y-2 = 3
Therefore y = 5.
Hence solved. x = 4, y = 5
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