Question

solve the following systems of equations by elimination method
x/2+2y/3=-1
x - y/3=3
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Answer 1

Hope it help if

Step-by-step explanation:

x/2 + 2 y/3

(3x+4y)/6 = -1

3x + 4y = -6 (equation 1)

Now,

x-y/3 = 3

(3x-y)/3 = 3

3x-y = 9(equation 2)

By elimination method

subtract (1)&(2)

3x+4y=-6

3x-y=9

or,5y= -15

or, y = -15/5

:y = 3

putting the value of y in equation 2

3x -(-3) =9

or, 3x+3 = 9

or, 3x = 3

: X =1

Hence X = 1 & y = 3