Question

Solve the following systems of equations graphically:
2x + 3y = 4
x – y + 3 = 0

Answer 1

Concept :

To draw the graph of a linear equation in two variable a series of steps to be followed which is given below:

• Step I:Obtain the linear equation.  Let the equation be  ax + by + c = 0
• Step II: Express one unknown quantity in terms of other here. Express y in terms of x to get y = - (ax + c /b)
• Step III: For any two values of x, calculate the corresponding values of y  from the expression in step II to obtain two solutions say (x1, y1 and( x2 ,y2)
• Step IV: plot the points  (x1, y1 and( x2 ,y2)  on graph paper on a suitable scale.
• Step V:Draw a  line passing through points marked in step IV. The line so obtained is the graph of the equation  ax + by + c = 0  

 

Given:  

2x + 3y = 4

x – y + 3 = 0

 

Solution :

2x + 3y = 4 passes through (-1, 2) and (2, 0,)

x - y + 3 = 0 passes through (1, 4) and (0, 3)

Two lines intersect at a point A  (-1, 2)

Hence x is - 1 and y is 2.

Table and the Graph of the given  systems of equations are  in the  attachment below :  

Hope this answer will help you…

 

Some more questions from this chapter :  

Solve the following systems of equations graphically:

2x-3y+13=0

3x-2y+12=0

https://brainly.in/question/15918176

 

Solve the following systems of equations graphically:

x – 2y = 6

3x – 6y = 0

https://brainly.in/question/15918172

Answer 2

$\huge\mathcal{Answer:}$

First eq:-

$2x + 3y = 4$

$2x = 4 - 3y$

$x = \frac{4 - 3y}{2}$

when y=o

$x = \frac{4 - 3 \times 2}{2} = - 1$

when y=2

$x = \frac{4 - 3 \times 2}{2} = - 1$

Second eq:-

$x - y + 3 = 0$

$x = y - 3$

when y=3

$x = 0$

When y=4

$x = 1$

_________________________

$x \: \: \: \: 0 \: \: \: \: 1$

$y \: \: \: \: 3 \: \: \: \: 4$