Question

Solve the following systems of equations:
$2x -\frac{3}{y}=9$
$3x +\frac{7}{y}=2, y \neq 0$

Answer 1

Given :  

2x - 3/y = 9  …………...( 1 )

3x + 7/y  = 2…………...( 2 )

On multiplying equation (1) by 3 and equation (2) by 2 :  

6x - 9/y = 27 ………..(3)

6x + 14/y = 4 ………..(4)

On subtracting eq (3) from (4) :

6x + 14/y = 4

6x - 9/y = 27

(-)  (+)  (-)

-----------------

23/y = - 23

y = -23/23

y = - 1  

On putting y = - 1 in eq (3)  we get :  

6x - 9/y = 27

6x - 9/-1 = 27

6x + 9 = 27

6x = 27 - 9

6x = 18

x = 18/6

x = 3

Hence, the value of the given system of equation is x = 3   and y = - 1.

Hope this answer will help you…

 

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Solve the following systems of equations:

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Answer 2

Answer:

Given,

Distance travelled on first trip = 165.9 km

Distance travelled on second trip = 102.04km

Total distance travelled = 165.9 + 102.04 = 267.94 km