Question

Solve the following systems of equations:

$\frac{1}{7} x + \frac{1}{6} y = 3$
$\frac{1}{2}x - \frac{1}{3}y = 3$
Please give me real answer. No copy paste, as a value is different in this one. I'll surely mark you brainliest if you give your best!


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Answer 1

Answer:

$\sf\dfrac{126}{11}$, $\sf\dfrac{90}{11}$

Step-by-step explanation:

Multiply 42 to the first equation.

$6x+7y=126$ ... (1)

Multiply 6 to the second equation.

$3x-2y=18$ ... (2)

We have to solve for one variable.

A suitable method will be canceling x.

To cancel x we are multiplying 2 × (2).

$6x-4y=36$ ... (3)

Now do (1)-(3)

$7y+4y=126-36$

$11y=90$ ... (4)

Before finding y, let's use (4) again.

We could cancel y this time.

$33x-22y=198$ [ (2) × 11 ]

$22y=180$ [ (4) × 2 ]

To cancel y: Add the above.

$33x=378$

∴$x=\sf\dfrac{\cancel{378}}{\cancel{33}}=\sf\dfrac{126}{11}$ ∴$y=\sf\dfrac{90}{11}$

Answer 2

Answer:

y=19/11

Step-by-step explanation:

hope it helps you