Solve the following systems of equations:
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Given pair of system of equation :
1/7x + 1/6y = 3 …………...( 1 )
1/2x - 1/3y = 5 …………...( 2 )
Elimination method is used to solve this Linear pair of Equations:
On multiplying eq 2 by 1/2 :
1/4x - 1/6y = 5/2 ……….... (3)
On adding equations (1) and (3) :
1/7x + 1/6y = 3
1/4x - 1/6y = 5/2
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1/7x + 1/4x = 3 + 5/2
(4 + 7)/28x = (6 + 5)/2
11/28x = 11/2
1/28x = ½
28x = 2
x = 2/28
x = 1/14
On putting x = 1/14 in eq (1) we get :
1/7x + 1/6y = 3
1/7(1/14) + 1/6y = 3
1/(½) + 1/6y = 3
1 × 2/1 + 1/6y = 3
2 + 1/6y = 3
1/6y = 3 - 2
1/6y = 1
6y = 1
y = 1/6
Hence, the value of the given system of equation is x = 1/14 and y = 1/6.
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x + y/2 = 4
x/3 + 2y = 5
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Solve the following systems of equations:
√2x - √3y = 0
√3x - √8y = 0
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