Question

Solve the following systems of equations:
$\frac{2}{x}+ \frac{3}{y} = \frac{9}{xy}$
$\frac{4}{x}+ \frac{9}{y}=\frac{21}{xy}, x \neq 0,y \neq 0$

Answer 1

Given pair of system of equation :  

2/x +  3/y =  9/xy …………...( 1 )

4/x + 9/y = 21/xy …………...( 2)

On multiplying eq 1 & 2 by xy :

2y + 3x = 9 ………….(3)

4y + 9x = 21 ……….(4)

On multiplying eq 3 by 3 :  

6y + 9x = 27 ………(5)

On subtracting equation (4) from eq (5) we get :  

6y + 9x = 27

4y + 9x = 21

(-)  (-)  (-)

-------------------

2y = 6

y = 6/2

y = 3

On putting y = 3 in equation (4) we get :  

4y + 9x = 21

4 × 3 + 9x = 21

12 + 9x = 21

9x = 21 - 12

9x = 9

x = 9/9

x = 1

Hence, the value of the given system of equation is x = 1   and y = 3

Hope this answer will help you…

 

Some more questions from this chapter :  

Solve the following systems of equations:

15/u + 2/v = 17  

1/u + 1/v = 36/5

https://brainly.in/question/17146456

 

Solve the following systems of equations:

3/x -  1/y = - 9  

2/x + 3/y = 5

https://brainly.in/question/17147636

Answer 2

Answer:

Hope it helps you.....