Question

Solve the following systems of equations:
$x+2y=\frac{3}{2}$
$2x+y=\frac{3}{2}$

Answer 1

Given :  

x + 2y = 3/2…………...( 1 )

2x + y = 3/2…………...( 2 )

Elimination method is used to solve this Linear pair of Equations:

On multiplying equation (2) by 2 :  

4x + 2y = 3 ………..(3)

On subtracting equations (1) from eq  (3) :

4x + 2y = 3

x + 2y = 3/2

(-)  (-)  (-)

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3x   = 3 - 3/2

3x = (6 - 3)/2

3x = 3/2

x = 3/2 × 1/3

x = ½

 

On putting x = 1/2 in eq (3)  we get :

4x + 2y = 3

4 × ½ + 2y = 3

2 + 2y = 3

2y = 3 - 2

2y = 1

y = 1/2

Hence, the value of the given system of equation is x = ½   and y = ½ .

Hope this answer will help you…

 

Some more similar questions from this chapter :  

Solve the following systems of equations:

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Answer 2

$x + 2y = \frac{3}{2} \\ \\ 2x + y = \frac{3}{2} \\ \\ = > x + 2y = 2x + y \\ \\ = > x = y$$x + 2y = \dfrac{3}{2} \\ \\ = > 3x = \dfrac{3}{2} \\ \\ = > x = y = \dfrac{1}{2}$