Question

solve the following systems of equations x+y=2 and 2x+2y=4

Answer 1

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Answer 2

Answer:

ANSWER

Equation I:-  2x+y=5

Equation II:-  x+2y=4

∴ We multiply Equation I by 2.

(2x+y=5)×(2)=(4x+2y=10)

We get equation III =4x+2y=10

Now, we subtract equation III & equation II.

(4x+2y=10)−(x+2y=4)

∴(4x−x)+(2y−2y)=(10−4)

∴(3x)+(0)=(6)

∴3x=6

∴x=36=2

We get x=2.

Now we substitute x=2  in equation II.

Equation II:-  x+2y=4

∴2+2y=4

∴2y=4−2

∴2y=2

∴y=2/2

∴y=1

Solving given equations, we get : x=2,y=1.

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