solve the following systems of linear cramers rule
x+y+z=2,2x+4y+2z=4,x-2y-z=0
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x + y + z = 2; 2x – y = 0; 2y – z = 1 The matrix equation corresponding to the system is Therefore the solution is (1, 2, 3)Read more on Sarthaks.com - https://www.sarthaks.com/864864/solve-by-cramer-rule-x-y-z-2-2x-y-0-2y-z-1
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