Question

Solve the following
$cos {}^{2} 45 + \sin 45 \times \cos 30 + \sin {}^{2} 60 \div \cos {}^{2} 45$
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Answer 1

Step-by-step explanation:

cos^245+sin45×cos30+sin^2 60÷cos^2 45

=(1/√2)^2+1/√2×√3/2+(√3/2)^2÷(1/√2)^2

=1/2+√3/2√2+3/4÷1/2

=1/2+√3/2√2+3/2

=2+√3/2√2