Question

solve the following
$\frac{4}{5} \times ( \frac{3}{9} + \frac{2}{3} )$

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Answer 1

$\large{\mathtt{\red{\underbrace{\overbrace{\blue{\boxed{\boxed{\pink{«Answer»}}}}}}}}}$

$= > \frac{4}{5 } \times ( \frac{3}{9} + \frac{2}{3})$

$= > \frac{4}{5} \times ( \frac{3 + 6}{9} )$

$= > \frac{4}{5} \times \frac{9}{9}$

$= > \frac{4}{5} \times \frac{1}{1}$

$= > \frac{4}{5} \times 1$

$= > \frac{4}{5}$

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Answer 2

Question

solve the following

$\frac{4}{5} \times ( \frac{3}{9} + \frac{2}{3} )$

Answer

$\large \bf\frac{4}{5} \times ( \frac{3}{9} + \frac{2}{3})$

$\rightarrowtail\large \bf\frac{4}{5} \times ( \frac{3}{9} + \frac{2}{3})$

$\rightarrowtail\large \bf\frac{4}{5} \times ( \frac{(3 \times 1) +( 3 \times 2)}{9} )$

$\rightarrowtail\large \bf\frac{4}{5} \times ( \frac{3 + 6}{9} )$

$\rightarrowtail\large \bf\frac{4}{5} \times ( \frac{9}{9} )$

$\rightarrowtail\large \bf\frac{4}{5} \times \frac{9}{9}$

$\rightarrowtail\large \bf\frac{4}{5} \times \cancel\frac{9 {}^{1} }{9 {}^{1} } \tiny\tt{9}$

$\rightarrowtail\large \bf\frac{4}{5} \tiny{ans}$

Hence, the answer is $\large \bf\frac{4}{5}$