Question

Solve the following trigonometric equation for ​0 ≤ x ≤ 2π​. Explain your process.

cos2x - 1 = 0

Answer 1

Answer:

thank me and brainlist me Next, solve the 2 basic equations: sin x = 0, and cos x = 1. Transformation process. ... F(x) = 2cos 2x.cos x + cos 2x = cos 2x(2cos x + 1 ) = 0. ... or 4x−π3=5π6+2πk for integer k . ... How do you solve for x in 3sin2x=cos2x for the interval 0≤x<2π ... How do you find the exact value given that tan(x)=1/2 from pi<x<3pi/2?

Step-by-step explanation: