Solve the following trigonometric equation for A<_0°<_360°
tanA + tan2A + tan3A = 0
Answers
Answered by
0
Answer:
tan @=0° { # @= thita / A }
Step-by-step explanation:
i thik that, 0°<_A<_360°
tan A + tan 2A + tan 3A = 0
tan 6A =0
6A = 0
A = 0
tan A = 0°
❥ ❤✖♡
Similar questions