Math, asked by kiransandeep44paiurj, 1 year ago

solve the following two linear equations graphically :x-y=8,3x - 3y=16

Answers

Answered by ashutoshsbcpf4yjc
55

Answer:

hey mate your answer is in this attachment and even the graph

Step-by-step explanation:

I hope you understood

if the answer is correct

mark as brainlieast

Attachments:
Answered by jhangir789
3

The two linear equation is, $(0,-8) \quad 2-\frac{10}{3}$.

What is two linear equations?

  • An equation is said to be linear equation in two variables if it is written in the form of ax + by + c=0, where a, b & c are real numbers and the coefficients of x and y, i.e a and b respectively, are not equal to zero.
  • For example, 10x+4y = 3 and -x+5y = 2 are linear equations in two variables.

According to the question:

$$\begin{aligned}&x-y=8,3 x-3 y=16 \\&\frac{a_{1}}{a_{2}}=\frac{1}{3}, \frac{b_{1}}{b_{2}}=\frac{-1}{-3}=\frac{1}{3} \frac{c_{1}}{c_{2}}=\frac{8}{16}=\frac{1}{2}\end{aligned}$$$$

\therefore \frac{\mathrm{a}_{1}}{\mathrm{a}_{2}}=\frac{\mathrm{b}_{1}}{\mathrm{~b}_{2}} \frac{\mathrm{c}_{1}}{\mathrm{c}_{2}}$$

therefore the linear equation are consistent.

therefore They have infinity solutions.

x y=8 \quad x+3 y=16\\x$ y $(x, y) xy $(x, y) 0\\$-8 \quad(0,-8) \quad 2-\frac{10}{3}$

Hence,  two linear equation is, $(0,-8) \quad 2-\frac{10}{3}$.

Learn more about two linear equation here,

https://brainly.in/question/18592881?msp_poc_exp=5

#SPJ2

Attachments:
Similar questions