Math, asked by itzcottoncandy65, 25 days ago

solve the following urgent !!​

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Answers

Answered by ssurash99
0

Answer:

x= 5 or 5/2

Step-by-step explanation:

solve the equation

((x-1)(x-4)+(x-3)(x-2))/((x-2)(x-4))=10/3

((x²-5x+4+x²-5x+6)/((x-2)(x-4))=10/3

6x²-30x+30=10x²-60x+80

4x²-30x+50=0

2x²-15x+25=0

(x-5)(2x-5)=0

x= 5 or 5/2

Answered by bagkakali
0

Answer:

(x-1)/(x-2)+(x-3)/ (x-4)=3 1/3

=> (x-1)(x-4)+(x-2)(x-3)=10/3.(x-2)(x-4)

=> 3{x^2-x-4x+4+x^2-2x-3x+6}=

10(x^2-2x-4x+8)

=> 3(2x^2-10x+10)=10(x^2-6x+8)

=> 6x^2-30x+30=10x^2-60x+80

=> 10x^2-60x+80-6x^2+30x-30=0

=> 4x^2-30x+50=0

=> 2x^2-15x+25=0

=> 2x^2-10x-5x+25=0

=> 2x(x-5)-5(x-5)=0

=> (x-5)(2x-5)=0

=> x-5=0

=> x=5

again, 2x-5=0

=> 2x=5

=> x=5/2=2 1/2

so , x=5 , 2 1/2

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