Question

solve the following using elimination and cross multiplication methods 2x+3y-6=0 7x-9y+16=9​

Answer 1

Answer:

Ans. Let the present age of Aftab = x

           And, present age of his daughter is represented as = y

           Seven years ago,

           Aftab’s age = x – 7

           Age of Aftab’s daughter = y – 7

           According to the question,

           (x – 7) = 7 (y – 7 )

           x – 7 = 7 y – 49

           x – 7y = – 49 + 7

           x – 7y = – 42 …           (i)

           x = 7y – 42

           Putting y = 5, 6 and 7, we get

           x = 7 × 5 – 42 = 35 – 42 = – 7

           x = 7 × 6 – 42 = 42 – 42 = 0

           x = 7 × 7 – 42 = 49 – 42 = 7

           

           Three years from now,

           Aftab’s age = x + 3

           Age of Aftab’s daughter = y + 3

           According to the question,

           (x + 3) = 3 (y + 3)

           x + 3 = 3y + 9

           x – 3y = 9 – 3

           x – 3y = 6 …           (ii)

           x = 3y + 6

           Putting, y = – 2, –1 and 0, we get

           x = 3 × – 2 + 6 = – 6 + 6 =0

           x = 3 × – 1 + 6 = – 3 + 6 = 3

           x = 3 × 0 + 6 = 0 + 6 = 6

           

           Algebraic representation

           From equation (i) and (ii)

           x – 7y = – 42 …           (i)

           x – 3y = 6 …                  (ii)

Answer 2

Refer to the attachment for answer

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