Question

solve the following using factorisation: 5(x/x+1)^2 - 4(x/x+1) -1=0, x ≠ -1

Answer 1

Answer:

Quadratic equation:

ax²+bx+c=0; a,b,c € R

=

− ±

2

− 4

2



If b²-4ac > 0, it has two real roots



If b²-4ac = 0, it has a unique root



If b²-4ac < 0, it does not have a real root

.

Special cases of quadratic equation

Given ax²+2bx+c=0;

=

−±

2

−

Viet theorem:

x²+px+q=0;

1 + 2 = −

1 ∗ 2 =