solve the following using identities [2/3a +3/4b]^2
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Answer:
Step-by-step explanation:
we know,
(a+b)² = a²+2ab+b²
therefore,
(2/3a+3/4b)² = (2/3a)² + 2 (2/3a)(3/4b) + (3/4b)²
i.e.
4/9a²+ab+9/16b²
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