solve the following using laws of exponent.
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Answer:
(a) (9/-5) ^2×(5/-3) ^3×(5/3) ^6
when we reciprocal it. So, digit come in
addition.
(81/25) ×(125/-9) ×(15, 625/729)
81/25×125/-9×15, 625/729
158,203,125/-6, 536 //ans
(b) [(-7/9×-9/7)^-3 ]÷(-7/9) ^-3
[(63/63) ^-3]÷(-7/9) ^-3
(63/63×-7/9) ^-3
(-441/567) ^-3
(567/-441) ^3
182,284,263/388, 962//ans
(c) (2/-3) ^4×(-3/2)
(16/81) ×(-3/2)
16/81×-3/2
-48/162// ans
(d) (-3/7) ^2×-3
(-3/7) ^-6
(7/-3) ^6
117,649/729
(e)[ (5×2) ^-2]×10^2
(10^-2) ×10^2
(1/10) ^2×10^2
(1/10×10) ^2
(1) ^2
1// ans
(f) [(-1/3)^ -4-(-2) ]^3
[(-1/3) ^-2]^3
(-1/3) ^-2×-3
(-1/3) ^-5
(3/-1) ^5
243/-1// ans
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