Question

solve the following using laws of exponents {(-1/3)-⁴÷(-1/3)-⁵}³​

Answer 1

Answer:

(-3)^-11

Step-by-step explanation:

We know that,     (a)^m / (a)^n = (a)^m-n

{(-1/3)-⁴÷(-1/3)-⁵}³​

$=\frac{(-1/3)^{-4} }{(-1/3)^{-5*3} } \\=\frac{(-1/3)^{-4} }{(-1/3)^{-15} }\\={(-1/3)^{-4-(-15)} }\\={(-1/3)^{(-4+15)} }\\={(-1/3)^{11} }\\={(-3)^{-11} }$