Question

solve the following using laws of exponents (-3/2)-⁴×(-3/2)​

Answer 1

Answer:

Consider the following:

1. 2³ × 2² = (2 × 2 × 2) × (2 × 2) = 23+2 = 2⁵

2. 3⁴ × 3² = (3 × 3 × 3 × 3) × (3 × 3) = 34+2 = 3⁶

3. (-3)³ × (-3)⁴ = [(-3) × (-3) × (-3)] × [(-3) × (-3) × (-3) × (-3)]

= (-3)3+4

= (-3)⁷

4. m⁵ × m³ = (m × m × m × m × m) × (m × m × m)

= m5+3

= m⁸

From the above examples, we can generalize that during multiplication when the bases are same then the exponents are added.

aᵐ × aⁿ = am+n

In other words, if ‘a’ is a non-zero integer or a non-zero rational number and m and n are positive integers, then

aᵐ × aⁿ = am+n

Similarly, (ab)ᵐ × (ab)ⁿ = (ab)m+n

(ab)m×(ab)n=(ab)m+n