Question

solve the following using suitable arrangement of property . 102×103​

Answer 1

Answer:

102 ×103

(100 + 2) (100 + 3)

using identity (x + a ) ( x + b) = x^2 + (a + b)x +ab

= ( 100)^2 + ( 2 + 3) 100 + 2 × 3

= 10000 + 500 + 6

= 10506 answer

hope you understand

Answer 2

Step-by-step explanation:

Given

102×103

Now we can write,

(100+2)(100+3)

The identity which will use here is (x+a) (x+b).

here,x = 100

a = 2

b = 3

(x+a) (x+b) = x^2+(a+b)x+a×b

= 100×2+(2+3)×100+2×3

= 10000+500+6

= 10506