Question

Solve the following x²-2x=48​

Answer 1

Solution :

$\: \: \: \: \: \: {x}^{2} - 2x = 48$

$= > {x}^{2} - 2x - 48 = 0$

$= > {x}^{2} - 8x + 6x - 48 = 0$

$= > x(x - 8) + 6(x - 8) = 0$

$= > (x - 8)(x + 6) = 0$

$= > x - 8 = 0 \: \: \: \: or \: \: \: \: x + 6 = 0$

$= > x = 8 \: \: \: \: or \: \: \: \: x = - 6$

Answer 2

Answer:

x^2-x(8-6)-48=0

x^2-8x+6x-48=0

x(x-8)+6(x-8)=0

(x+6)(x-8)=0

x=-6,x=8