Question

solve the following (y^2+5y)^2(y^2+5y-2)-24=0​

Answer 1

Answer:

y2+5y)(y2+5y−2)−24=0

Let, y2+5y=a

a(a−2)−24=0

a2−2a−24=0

a2−6a+4a−24=0

a(a−6)+4(a−6)=0

(a−6)(a+4)=0

a−6=0 or a+4=0

By resubstituting,

y2+5y=a

y2+5y−6=0 or y2+5y+4=0

y2+6y−y−6=0 or y2+4y+y+4=0

y(y+6)−1(y+6)=0 or y(y+4)+1(y+4)=0

(y+6)(y−1)=0 or (y+4)(y+1)=0

y−1=

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