Question

solve the followingvpairs of equations by reducing them to a pair of linear equations 4byx+3y=14 and 3byx_4y=23​

Answer 1

Step-by-step explanation:

4byx+3y=14 and 3byx_4y=23

y(4bx +3)= 14 and y(3bx-4) = 23

4bx+3 = 14/y and 3bx-4 = 23/y

4bx-14/y =-3

3bx-23/y = 4

let bx= u , 1/y=v

so linearequation becomes

4u-14v= -3.............,............1

3u-23v= 4 .............,...........2

by elimination method

(4u-14v= -3 ) x 3

(3u-23v= 4 ) x 4

12u-42v = -9

12u-92v = 16

- + - (changing sign)

____________

0 + 50v = -25

v = -25/50

v = -1/2

now put value of v in equation 1

4u -14x(-1/2) = -3

4u + 7 = -3

4u= -3-7

4u = -10

u = -10/4

u = -5/2

we know that

u = xb v = 1/y

so,

-5/2 = xb y = 1/v

-5/2b = x y = -2

I hope it helps to you!