Question

solve the follwing system of equations 1/7x+1/6y=3,1/2x-1/3y=5

Answer 1

here is your answer
$\frac{1}{7x} + \frac{1}{6y} = 3 \: \: \: \: \: \: (eq - (1)\\ \\ \frac{1}{2x} - \frac{1}{3y} = 5 \: \: \: \: \: \: (eq - (2)$
according to eq (1)
$\frac{1}{7x} + \frac{1}{6y} = 3 \\ \\ \frac{1}{7x} = 3 - \frac{1}{6y} \\ \\ \frac{1}{7x} = \frac{18y - 1}{6y} \\ \\ 7x = \frac{6y}{18y - 1} \\ \\ x = \frac{6y}{(18y - 1)7} \\ \\ x = \frac{6y}{126y - 7}$
putting this Value in equation 2

$\frac{1}{2x} - \frac{1}{3y} =5 \\ \\ \frac{1}{2 \times ( \frac{6}{126y - 7} )} - \frac{1}{3y} = 5 \\ \\ \frac{1 \times (126y - 7)}{2 \times 6} - \frac{1}{3y} = 5 \\ \\ \frac{126y - 7}{12} - \frac{1}{3y} = 5$
than find the Value of y than x

hope this helps you
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