Math, asked by alarconerica, 3 months ago

Solve the general solution for 4tan2 u − 1 = tan2 u

Answers

Answered by Naina3843
7

Answer:

4 \tan {}^{2} u - 1 =  \tan {}^{2} u

3 \tan{}^{2}  = 1

 \tan {}^{2} u =  \frac{1}{3}

 \tan \: u \:  =  + \frac{1}{ \sqrt{3} }

or \:  \tan \: u \:  =  -  \frac{1}{ \sqrt{3} }

 \tan \: u \:  =  \frac{ \sqrt{3} }{3}

or \:  \tan \: u \:  =  -  \frac{ \sqrt{3} }{3}

hope it will help you....

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