Question

Solve the given circuit​

Answer 1

Your answer is in the attachment.!

Answer 2

Answer:

16 ohm.

Explanation:

{(3+3)||(6+6)}+{(3+3)||(6+6)}+{(3+3)||(6+6)}+{(3+3)||(6+6)}

={6||12}+{6||12}+{6||12}+{6||12}

$\frac{6 \times 12}{12 + 6} + \frac{6 \times 12}{12 + 6} + \frac{6 \times 12}{12 + 6} + \frac{6 \times 12}{12 + 6} \\ \frac{72}{18} + \frac{72}{18} + \frac{72}{18} + \frac{72}{18} \\ 4 + 4 + 4 + 4 = 16$

You can solve it in very shor:

as every loop is equal just calculat 1st.

that is {(3+3)||(6+6)}

{6||12}

12/3

4

all the 4 similar loop is connected in series.

so Equivalent resistance is 4+4+4+4 or 4×4=16.

there is no way to say thanks but edit ans.

THANKS A LOT.