Question

Solve the given equation.
64x^3+8=0

Answer 1

$64 {x}^{3} = 0 - 8 \\ 64x ^{3} = - 8 \\ x ^{3} = - 8 \div 64 = - 1 \div 8 \\ x = \sqrt[3]{ - 1 \div 8} = - 1 \div 2$
here is your ans=-1/2