Question

Solve the given equation by factorisation method 3y²-14y+8=0

Answer 1

Answer:

3y^2 - 12y - 2y + 8 = 0

3y ( y - 4 ) - 2 ( y - 4 ) = 0

( y - 4 ) ( 3y - 2 ) = 0

y - 4 = 0

y = 4

3y - 2 = 0

y = 2/3

hope it helps you.............

Answer 2

Answer:-

3y²-12y-2y+8=0

3y (y-4)- 2(y-4)=0

(y-4) (3y-2)=0

y-4=0.   OR.    3y2=0

y=4.       OR.    3y=2

y=4.       OR.     y=2/3

The root of given quadratic equations are 4 and 2/3.