Solve the given equation by factorisation method 3y²-14y+8=0
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Answered by
9
Answer:
3y^2 - 12y - 2y + 8 = 0
3y ( y - 4 ) - 2 ( y - 4 ) = 0
( y - 4 ) ( 3y - 2 ) = 0
y - 4 = 0
y = 4
3y - 2 = 0
y = 2/3
hope it helps you.............
Answered by
2
Answer:-
3y²-12y-2y+8=0
3y (y-4)- 2(y-4)=0
(y-4) (3y-2)=0
y-4=0. OR. 3y2=0
y=4. OR. 3y=2
y=4. OR. y=2/3
The root of given quadratic equations are 4 and 2/3.
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