Solve the given equation by the method of completing the squares: x2 + 12x – 45 = 0
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Answered by
98
x^2 + 12 x - 45 = 0
=> x^2 + 12x =45
add (6)^2 both side
=> x^2 + 12x + (6)^2 = 45 + (6)^2
=> x^2 + 2. (6).x + (6)^2 = 81 =(9)^2
=>(x + 6)^2 = (9)^2
=> (x + 6)^2 -(9)^2 = 0
use formula,
a^2 - b^2 = (a - b)(a + b)
now,
=>(x + 6 -9)(x + 6 + 9)=0
=> x=3 , -15 , hence roots of equation is 3 and -15
=> x^2 + 12x =45
add (6)^2 both side
=> x^2 + 12x + (6)^2 = 45 + (6)^2
=> x^2 + 2. (6).x + (6)^2 = 81 =(9)^2
=>(x + 6)^2 = (9)^2
=> (x + 6)^2 -(9)^2 = 0
use formula,
a^2 - b^2 = (a - b)(a + b)
now,
=>(x + 6 -9)(x + 6 + 9)=0
=> x=3 , -15 , hence roots of equation is 3 and -15
Answered by
15
Answer: answer is 3;-15
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