Question

solve the given equation by the method of factorisation:2x^2+√6x-6=0​

Answer 1

The solution of this equation is x = -√6 or √6/2.

Given,

A quadratic equation 2x²+√6x-6=0.

To Find,

The solution of this equation.

Solution,

The given quadratic equation is

2x²+√6x-6=0

Now, using the middle term splitting method

2x²+√6x-6=0

Splitting the middle term √6x as 2√6x-√6x

So,

2x²+2√6x-√6x-6=0

2x(x+√6)-√6(x+√6) = 0

(x+√6)(2x-√6) = 0

So,

x = -√6 or √6/2

Hence, the solution of this equation is x = -√6 or √6/2.

#SPJ3

Answer 2

Given,

A quadratic equation 2x²+√6x-6=0.

To Find,

The solution of this equation.

Solution,

The given quadratic equation is

$2x^{2}+\sqrt{6}x-6=0$

Now, using the middle term splitting method

• The general form of the polynomial is $ax^{2} +bx +c=0$
• The sum product form is the product of the middle term after splitting must be equal to a × c.
• and the sum must be equal to b.

2x²+√6x-6=0 ,

$a=2\\b=\sqrt{6}\\ c=-6$

Splitting the middle term √6x as 2√6x-√6x

So,

$2x^{2} +2\sqrt{6}x-\sqrt{6}x-6=0$

$2x(x+\sqrt{6})-\sqrt{6}(x+\sqrt{6})=0$

$(x+\sqrt{6})(2x-\sqrt{6})=0$

So,

$x=-\sqrt{6} , \frac{\sqrt{6} }{2}$

Hence, the solution of this equation is x = -√6 or √6/2.

#SPJ2