Question

solve the given equation step by step​

Answer 1

We need to understand that years like 2004, 2008, 2000 having 2 odd day because these are divisible by 4. The year not divisible by 4 is having 1 odd day only (simply means 2004, 2008, 2000 having 29 days in feb so total 366 days) (2001, 2002, 2003 like which are not div by 4 having only 28 day in feb so tot 365 days).

If you confused about odd day means just divide the total number of days by 7.

366/7 = 2 remainder so two odd days.

365/7 = 1 remainder so one odd day.

GOT IT:).

So let me come to our problem.

8th Feb, 2005:

So total days is.

Jan = 31.

Feb = till 8 so 31+8=39 is there in 2005.

8th Feb, 2004:

So calculate from 2004 8th feb to 2005 8th feb (we already calculate 39 days in the 2005 till feb).

Now 2004 feb contains 29 days we just need to calculate from 8th only.

Feb 8th to feb 29 = 21 days.

March = 31.

Apr = 30.

May = 31.

.

.

Dec=31.

Already we calculate the 2005 before it contains total of 39 days.

So add all these.

39 (2005's tot days because till feb means jan 31 day+ feb 8 day) +21 (2004 feb because from 8 to 29 only need) +31 (mar 2004) +30 (apr 2004) +...+31 (dec) = 366.

Now 366/7 = 2 days remainder.

0 1 2 3 4 5 6.

S m t w t f s.

2005 feb 8 is Tuesday.

Now need 2004 feb 8. Here calculate from higher to lower year so just minus the reminder 366/7 = 2 from Tuesday.

SO SUNDAY.