Question

Solve the given equation: $x^{2} -x+2=0$.

Answer 1

$x {}^{2} - x + 2 = 0 \\ {x}^{2} - (2 - 1)x + 2 = 0 \\ {x}^{2} - 2x + x + 2 = 0 \\ x(x - 2) - 1(x - 2) = 0 \\ (x - 2)(x - 1) = 0 \\ \\ x - 2 = 0 \\ x = 2 \\ \\ x - 1 = 0 \\ x = 1$