Question

solve the given equation x²+4×-5=0 by completing square method​

Answer 1

Answer:

use( b/2)2 an solve in equation

Answer 2

Answer:

$x = - 2 \: \: or \: \: 0$

Step-by-step explanation:

Given :-

$equation = > \\ {x}^{2} + 4x - 5 = 0$

To solve this equation by completing square ,

you must follow the steps written below:-

1) split the middle term in the form =>(2abx)

$= > 4x = 2(1)(2)x$

like this, where a=1 and b=2

2) now , add and subtract the square of b.

$= > {x}^{2} + 4x - 5 + {2}^{2} - {2}^{2} = 0 \\ \\ = > {x}^{2} + 4x + {2}^{2} - {2 }^{2} - 5 = 0 \\ \\ = > {x}^{2} + 2(1)(2)x + 4 - 4 + 5 = 0 \\ \\ = > {x}^{2} + 2(1)(2)x + 4 = - 1$

3) it is in the form of the identity

${(a + b)}^{2} = {a}^{2} + 2ab + {b}^{2}$

4) compare with it and make it in this form :-

$here \:, \: \\ a = 1 \: x \: \: and \: \: b = 2 \\ hence \: the \: equation \: become:- \\ {(x+1)}^{2} \: = \: -1 \: \\ </p><p>either, \\ </p><p> \: x+1 \: = \: - 1. \: \: or \: \: x+1=1 \\ x=-1-1=-2 \: \: \: or \: x=1-1=0 \:$

hope it helps you .

mark it brainliest ☺️.