Math, asked by ghatgeprashant0, 9 months ago

solve the given equations (a+c)x-(a-c)y=2ab;(a+b)x-(a-b)y=2ab​

Answers

Answered by Anonymous
3

Answer:

(a+c)x − (a−c)y = 2ab     ....(1)

(a+b)x − (a−b)y = 2ab     ..(2)    

Adding (1) and (2), we get,      

(a+c+a+b)x − (a−c+a−b)y = 4ab

⇒(2a+b+c)x − (2a−b−c)y = 4ab

⇒(2a+b+c)x + (b+c−2a)y = 4ab    ...(3)

Subtracting (2) from (1), we get      

(c−b)x + (c−b)y = 0    

⇒(c−b)(x+y) = 0

⇒x + y = 0

⇒y = − x       ...(4)

putting the value of y in (3), we get      

(2a+b+c)x + (b+c−2a)(−x) = 4ab

⇒[(2a+b+c) −(b+c−2a)]x = 4ab

⇒(2a+b+c−b−c+2a)x = 4ab

⇒4ax = 4ab

⇒x = b

Now, from (4), we get

y = −b

so, x = b  and  y = − b  is the solution.

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