Question

Solve the given exponential equation ​

Answer 1

Step-by-step explanation:

3^2^2x=1/81

9^2x=9^-2

2x=-2

x=-1

Answer 2

Step-by-step explanation:

${3}^{4x} = \frac{1}{81}$

${( {3}^{x}) }^{4} = {( \frac{1}{3}) }^{4}$

${3}^{x} = \frac{1}{3}$

Taking log on both sides

$log( {3}^{x} ) = log( \frac{1}{3} )$

$x log(3) = log(1) - log(3)$

$log(1) = 0$

$x = \frac{ - log(3) }{ log(3) }$

$x = - 1$