Question

Solve the given exponential equation. A)2^x-1=8 B)8^x=√2

Answer 1

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Answer 2

Answer:

Answer:

\begin{lgathered}( \sqrt{2 {)}^{x} } = {2}^{8} \\ \frac{ {2}^{x} }{2} = {2}^{8} \\ \frac{x}{2} = 8 \\ x = 8 \times2 = 16 \\ \\ plzz \: mark \: its \: brainlist \: plzzz\end{lgathered}

(

2)

x

=2

8

2

2

x

=2

8

2

x

=8

x=8×2=16

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